python, spyders and scrapy developer -- 2

Käynnissä Julkaistu 3 vuotta sitten Maksettu toimituksen yhteydessä
Käynnissä Maksettu toimituksen yhteydessä

I request a developer with excellent knowledge in python, spiders and scrapy to make some fixes in an application based on python, conda and mini conda. PREFERABLY NOT FROM CHINA, I have already had problems with the quality of work of various developers there. IF YOU DON'T KNOW HOW TO MAKE A SPIDER AND A SCRAPY, DON'T POSTULATE, DON'T MAKE ME WASTE MY FUCKING TIME!!

JavaScript Python Tietojen kaavinta verkosta Tietojärjestelmäarkkitehtuuri Node.js

Projektin tunnus: #26729079

Tietoa projektista

10 ehdotusta Etäprojekti Aktiivinen 3 vuotta sitten

10 freelanceria on tarjonnut keskimäärin $45 tähän työhön

stankovic33

I am very interested in your proposal and can complete this project as you need. I am a professional for the React JS so have rich experience in React/Redux, Typescript, GraphQL, Appolo, scrapy, Next, Gatsby, Node/Espr Lisää

$35 USD 7 päivässä
(8 arvostelua)
4.8
Gerrard97

We are a team of Electrical and Electronics engineers and we are Excellent in the following areas: • PCB Designing-Proteus, Eagle. • Python • Embedded C Programming. • VHDL/Verilog • Microcontroller like Arduino, R Lisää

$35 USD 7 päivässä
(2 arvostelua)
4.3
ujjwalsahni93

I am currently working on web scrapping, and have good working knowledge of python. Let me know if you some quality work delivered.

$50 USD 7 päivässä
(0 arvostelua)
0.0
Oleksiy96

Hello Hope you are doing well from covid. I am an expert for building python scrapping tools for 3+ years, and ready for your project now. I have worked on many python scraping project before join freelancer. Please co Lisää

$60 USD 1 päivässä
(0 arvostelua)
0.0
NikitaYas

Good day. I'm interested in your project. I have about 3 years of scraping and 6 years of python programming experience. A big plus of using python is that everything will be automated and that I can write a program qu Lisää

$35 USD 7 päivässä
(0 arvostelua)
0.0