Suoritettu

# Matlab Plotting (Easy)

geothes suoritti tämän projektin onnistuneesti hintaan %selected_seller_sum_sub_30% %project_currencyDetails_sign_sub_31% (USD) / hour yhdessä päivässä.

###### Projektin budjetti
\$2 - \$8 USD / hour
1 päivä
6
###### Projektin kuvaus

I dont have Matlab, but must complete project asap. Winner will recieve \$5, PLEASE ONLY BID \$5.... This is very simple, thus why I am only offering a small price to complete. Need to produce the following plot based on criteria below. Please see attachment for better description.

1) Let x be parameterized by the curve x=16 sin^3?t and y be parameterized by the curve y= 13 cos?t-5 cos?2t-2 cos?3t-cos?4t. Plot this parameterized curve from 0?t<2?. Use a fairly large step size for t ( ?t?0.1).

2) Let the vector field on this parameterized curve be given by A_x=-cos?(tan^(-1)?((-48 sin^2?t cos?t)/(-13 sin?t+10 sin?2t+6 sin?3t+4 sin?4t ))?) and A_y=sin?(tan^(-1)?((48 sin^2?t cos?t)/(-13 sin?t+10 sin?2t+6 sin?3t+4 sin?4t ))?)

Using the quiver function, plot this vector field only along the curve x,y

Based solely on the picture you’ve plotted, why is the integral ???A ??(dl) ? ? equal to zero around the parameterized curve? What does this mean about ??(?×A ? ) ?dS ? ?