# Solve a math equation

• Tila: Closed
• Palkinto: ₹1000
• Vastaanotetut työt: 18
• Voittaja: praveen3007

## Kilpailun tehtävänanto

One package has a size of 10 cm * 5 cm * 3.6 cm.

The forwarder accepts a belt dimension of max. 300 cm.

The belt dimension is calculated as follows: 2 * width + 2 * height + longest side.

The longest side must not exceed 175 cm.

What is the maximum number of packages that can be delivered?

Write and solve the problem with a mathematical equation.

First answer wins the contest.

P.S:
The correct answer is 1380 boxes. No one has sent in the correct equation yet. I will reward the first one who figures it out.

Winner

## Työnantajan palaute

“Very smart and friendly! Thanks for solving my math problem.”

distributorch, Switzerland.

## Julkinen selvennystaulu

• ###### sriharivaila2000
• 1 kuukausi sitten

Wt was ur dimensions for the 1380 no of boxes.

• 1 kuukausi sitten
• ###### harshgupta3584
• 1 kuukausi sitten

MY QUESTION IS WHY YOU ARE UPLOADING SUCH QUESTION LOOK LIKES YOU ARE AN INTERESTING PERSON

• 1 kuukausi sitten
• Kilpailun järjestäjä
• 1 kuukausi sitten

P.S:
The correct answer is 1380 boxes. No one has sent in the correct equation yet. I will reward the first one who figures it out.

• 1 kuukausi sitten
• ###### xMECHATRONICSx
• 1 kuukausi sitten

Please check Sir. Thanks

• 1 kuukausi sitten
• ###### sriharivaila2000
• 1 kuukausi sitten

Equation ready sir have a look.

• 1 kuukausi sitten
• ###### sriharivaila2000
• 1 kuukausi sitten

Your equation is ready sir. Have a look.

• 1 kuukausi sitten
• ###### punitjalanpj1
• 1 kuukausi sitten

So, I have a couple of doubts.
1) Can I consider this belt as a box and you have to take the maximum number of packages in this box? as the belt gives me a picture whose height can be zero
2) The dimension formula given has nothing to do with the actual volume of the package right? The actual volume is still L*B*H?

• 1 kuukausi sitten
1. ###### punitjalanpj1
• 1 kuukausi sitten

So consider the longest side=100cm and the other sides to be 50-50 each
Now each box will take the area =10*5= 50 therefore we can have 100 boxes kept along the longest side and on the 50cm length and there will be a total of 50/3.6= 13.88= 13 such rows therefore you can fit 1300 boxes in that belt

• 1 kuukausi sitten
• ###### ANNDK13
• 1 kuukausi sitten

can you give the packaging illustration? I can't imagine how you tie the box with 10 levels

• 1 kuukausi sitten
• ###### sandip2k1in
• 1 kuukausi sitten

Please check the problem once again. Either the dimensions are wrong, or the given formula is wrong or the answer of 480 boxes is wrong.

• 1 kuukausi sitten
1. Kilpailun järjestäjä
• 1 kuukausi sitten

48 boxes side by side and 10 boxes on top of each other gives a total of 480 boxes with a volume of 10 * 50 * 172,8 cm (= belt dimension of 292,8cm)

• 1 kuukausi sitten
• ###### sandip2k1in
• 1 kuukausi sitten

However, according to the formula, the circumference of one box will be : 2*5+ 2*3.6+10= 27.2 cm. So a maximum belt dimension of 300 cm will be able to accommodate (300/27.2) or 11 boxes approx.

• 1 kuukausi sitten
• ###### sandip2k1in
• 1 kuukausi sitten

According to your reply, the dimension of 7 boxes is 80.4 cm. (2*10+2*5+2*3.6*7). So a dimension of 300 cm will be able to accommodate (300*7/80.4) or 26 boxes approx. How is the answer of 480 boxes possible?

• 1 kuukausi sitten
• ###### PDE3
• 1 kuukausi sitten

Coupple of questions. 1) 10x5x3.6: which dim represent width and height. (2) What is forwarder please?

• 1 kuukausi sitten
1. Kilpailun järjestäjä
• 1 kuukausi sitten

1) width and height are the shortest lengths (in this case 5 + 3.6).
2) forwarder means carrier / shipper / forwarding agent.

• 1 kuukausi sitten
• Kilpailun järjestäjä
• 1 kuukausi sitten

I got it solved in the meantime. The correct answer is 480 boxes. No one has sent in the correct equation yet. I will reward the first one who figures it out.

• 1 kuukausi sitten

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